Question

Find the perimeter and area of the sector of a circle of radius 6 cm with central angle 210°

Answer 1

Solution :

Given radius of the sector ( r ) = 6cm

central angle ( x° ) = 210°

Let the length of the arc = l cm

i ) l = ( x/360 )× 2πr

= ( 210/360 ) ×2 × 22/7 × 6

= 22 cm ---( 1 )

ii ) Perimeter of the sector = l + 2r

= 22 + 2 × 6

= 22 + 12

= 34 cm

iii ) Area of the sector ( A ) = ( x/360 )×πr²

= ( 210/360 ) × ( 22/7 ) × 6²

= 66 cm²

Therefore ,

Perimeter of the sector = 34 cm

area of the sector = 66 cm²

•••••

Answer 2

HELLO DEAR,

Given radius of the sector ( r ) = 6cm

central angle n = 210°

Let the length of the arc = l cm

l = ( n/360 )× 2πr

= ( 210/360 ) × 2 × 22/7 × 6

= 22 cm

Perimeter of the sector = l + 2r

= 22 + 2 × 6

= 22 + 12

= 34 cm

iii ) Area of the sector ( A ) = ( n/360 )×πr²

= ( 210/360 ) × ( 22/7 ) × 6²

= 66 cm²

I HOPE IT'S HELP YOU DEAR,

THANKS