Question

Find the perimeter and area of the triangle whose sides are of length 56cm 52 cm and 60cm respectively

Answer 1

lengths = 56,52 and 60
perimeter =sum of all sides
56+52+60
108+60
168cm
if you want answer in metre then divide it by 100
168/100
1.68m


HOPE IT HELPS YOUUU

Answer 2

✬ Perimeter = 168 cm ✬

✬ Area = 1344 cm² ✬

Step-by-step explanation:

Given:

• Length of sides of triangle are 56 cm , 52 cm and 60 cm respectively.

To Find:

• What is the perimeter and area of the triangle?

Solution: Let the sides of triangle be a , b and c.

• a = 52 cm
• b = 56 cm
• c = 60 cm

★ Perimeter of triangle = ( a + b + c ) units ★

$\small\implies{\sf }$ Perimeter = ( 52 + 56 + 60 ) cm

$\small\implies{\sf }$ Perimeter = 168 cm

Hence, The Perimeter of triangle will be 168 cm.

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Now, We have to find the area of the triangle by using Heron's Formula.

★ Semi Perimeter (S) = ( a + b + c /2 ) ★

$\small\implies{\sf }$ 52 + 56 + 60/2

$\small\implies{\sf }$ 168/2

$\small\implies{\sf }$ 84 cm.

★ Heron's Formula ∆ = √S (s – a) (s – b) (s – c) ★

$\small\implies{\sf }$ √84 (84 – 52) (84 – 56) (84 – 60) cm²

$\small\implies{\sf }$ √84 x 32 x 28 x 24 cm²

$\small\implies{\sf }$ √14 x 6 x 16 x 2 x 14 x 2 x 6 x 4 cm² [ Take common ]

$\small\implies{\sf }$ (14 x 6 x 4 x 2 x 2) cm²

$\small\implies{\sf }$ 1344 cm²

Hence, The area of triangle will be 1344 cm²