Question

find the perimeter and diagonal of a square whose area is 64 cm2

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Answer 1

Step-by-step explanation:

let side of the square be ' a ' .

area of square = 64

a^2 = 64

a = 8 cm.

perimetre of square = 4a = 4 (8) = 32 cm.

diagonal of square = root 2 × a = root 2 × 8 cm.

Answer 2

Given:-

•Area of a square=64cm²

To find:-

•Diagonal of the square

•Perimeter of the square

Solution:-

We know that area of a square,when a diagonal is given:-

$= > \frac{1}{2} {d}^{2}$

$= > \frac{1}{2} {d}^{2} = 64$

$= > {d}^{2} = 64 \times 2$

$= > {d}^{2} = 128$

$= > d = \sqrt{128}$

$= > d = 8 \sqrt{2} cm$

$=>Thus \: diagonal \: of\: the \: \\ square \: is \: 8 \sqrt{2} cm$

Now we know that,area of a square:-

=>(side)²

=>(side)²=64

$= > side = \sqrt{64}$

=>side=8cm

Perimeter of a square:-

=>4×side

=>4×8

=>32cm

Hence,perimeter of the square is 32cm.