Question

find the perimeter and diagonal of square whose length is 10 cm​

Answer 1

Answer:

Let □◻ABCD be the given square. l(diagonal AC) = 10 cm Let the side of the square be ‘x’ cm. In ∆ABC, ∠B = 90° [Angle of a square] ∴ AC2 = AB2 + BC2 [Pythagoras theorem] ∴ 102 = x2 + x2 ∴ 100 = 2x2 ∴ x2 = 100/2 ∴x2 = 50 ∴ x = 50−−√50 [Taking square root of both sides] = 25×2−−−−−√25×2 = 52–√52 ∴side of square is 52–√52 cm. = 4 x 52–√52 ∴ Perimeter of square = 202–√2 cmRead more on Sarthaks.com - https://www.sarthaks.com/850581/find-the-side-and-perimeter-of-a-square-whose-diagonal-is-10-cm

Step-by-step explanation:

hope it's help you

mark me as brainliest

have a nice day

Answer 2

Diagonal of a square= ✓2a

where

a=side

10=✓2a

a=10/✓2a

a= 5 ✓2cm

Perimeter of square=4a

=4×5 ✓2

= 20✓2

Therefore side and perimeter of the square is 5

✓2 cm and 20 ✓2cm