find the perimeter, area and length of diagonal of a rectangle, length =3.2,Breadth =2.4
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Hi ,
Dimensions of the rectangle ,
length ( l ) = 3.2 ,
Breadth ( b ) = 2.4
1 ) perimeter ( p ) = 2 ( l + b )
p = 2 ( 3.2 + 2.4 )
= 2 × 5.6
= 11.2 units
2 ) Area = lb
A = 3.2 × 2.4
A = 7.68 sq units.
3 ) length of the diagonal
d = √ l² + b²
= √ ( 3.2 )² + ( 2.4 )²
= √ 10.24 + 4.8
= √15.04
≈ 3.878
I hope this helps you.
:)
Dimensions of the rectangle ,
length ( l ) = 3.2 ,
Breadth ( b ) = 2.4
1 ) perimeter ( p ) = 2 ( l + b )
p = 2 ( 3.2 + 2.4 )
= 2 × 5.6
= 11.2 units
2 ) Area = lb
A = 3.2 × 2.4
A = 7.68 sq units.
3 ) length of the diagonal
d = √ l² + b²
= √ ( 3.2 )² + ( 2.4 )²
= √ 10.24 + 4.8
= √15.04
≈ 3.878
I hope this helps you.
:)
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