Question

find the perimeter area and length of diagonals of a rectangle having length 20m breadth 15m
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Answer 1

Answer:

Area of rectangle= 300$m^{2}$, perimeter = 70 m , diagonals of rectangle = 25 m

Step-by-step explanation:

Given length of the rectangle = 20 m

         breadth of the rectangle = 15 m

perimeter of rectangle =  $2 (l+b)$ =  2 (20+15)

                                                     = 2 ( 35) =70 m

area of the rectangle = $lb$ =  20 × 15 = 300$m^{2}$

diagonals of a rectangle = $\sqrt{ l^{2} + b ^{2} }$

                                          = $\sqrt{ 15 ^{2}+ 20 ^{2} }$

                                          = $\sqrt{ 225+ 400}$=   $\sqrt{ 625 }$=  

                                          = $\sqrt{ 25 ^{2} }$ = 25 m

Answer 2

Given - Length and breadth of rectangle

Find - Perimeter, area and length of diagonal

Solution - For given rectangle, perimeter is 70 metres, area is 300 metre² and diagonal is 25 metres.

Perimeter of rectangle can be calculated by the formula - 2(length + breadth)

Perimeter of rectangle = 2(20 + 15)

Perimeter of rectangle = 2*35

Perimeter of rectangle = 70 metres

Area of rectangle can be calculated by the formula - length*breadth

Area of rectangle = 20*15

Area of rectangle = 300 metre².

Diagonal of rectangle will be calculated by using Pythagoras theorem.

So, Diagonal² = Length² + Breadth²

Diagonal² = 20² + 15²

Diagonal² = 400 + 225

Diagonal = ✓625

Diagonal = 25 metres

Therefore, perimeter is 70 metres, area is 300 metre² and diagonal is 25 metres.