find the perimeter area and length of diagonals of a rectangle having length 20 m and breadth 15 m
Answers
Answered by
0
FIRSTLY AREA OF RECTANGLE =A×B
=15×20=300
SECONDLY DIAGONAL OF RECTANGLE
=(AB ) SQUARE×(BC)SQUARE=(AC)SQUARE
=(15)(15)+(20)(20)=(AC)SQUARE
=225+400=(AC)SQUARE
=625=(AC)SQUARE
=AC=25
siddhartranjan:
thanks bhai
Answered by
0
perimeter = 2(l+b) = 2X35 = 70n
area l*b = 20 X 15 = 300 meter square
area l*b = 20 X 15 = 300 meter square
Attachments:
Similar questions