Question

find the perimeter area and length of diagonals of a rectangle having length 20m breadth 15m

Answer 1

perimeter=2(l+b)
=2(20+15)
2(35)
perimeter =70m
diagnol length =root(l^2 +b^2)
=root(20^2 +15^2)
root(400+225)
root(625)
=25cm
diagnol length =25cm
area=l×b
area=20×15
area=300meters is answers

Answer 2

Hey dear friend

Length of a rectangle=20m (l)
Breadth of a rectangle=15m (b)

Perimeter of a rectangle=2(l+b)
Perimeter of a rectangle=2(15+20)
Perimeter of a rectangle=2*35
Perimeter of a rectangle=70m

Now,
Area of a rectangle=length*breadth
Area of a rectangle=20m*15m
Area of a rectangle=300m²

Now,

The diagonals of a rectangle are equal So, I only find one diagonal

By Pythagoras Theorem

Diagonal²=Length² +Breadth²
Diagonal²=20²+15²
Diagonal²=400+225
Diagonal²=625
Diagonal=✓625
Diagonal=25cm


Perimeter=70cm
Area =300cm²
LEngth of diagonal=25cm


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