Question

Find the perimeter of:
(a) a rectangle of length = 9 m 35 cm and breadth = 6 m 45 cm​

Answer 1

Answer by ADITYA NATH PATEL

perimeter of rectangle=2×( length+breadth)

= 2×(9m 35cm × 6m 45cm)

=2×15m 80cm

=31 m 60cm

Answer 2

Given:-

• Length of rectangle = 9m 35 cm
• Breadth of rectangle = 6m 45 cm

To find:- Perimeter of rectangle.

$\</strong><strong>l</strong><strong>a</strong><strong>r</strong><strong>ge\bf\underline\</strong><strong>p</strong><strong>u</strong><strong>r</strong><strong>p</strong><strong>l</strong><strong>e</strong><strong>{</strong><strong>Solu</strong><strong>tioN</strong><strong>:</strong><strong>-</strong><strong>}$

______________

Conversion:-

↦Length = 9m 35 cm

( 1 m = 100 cm)

35 cm = 35 / 100 m

= 0.35m

So , Length = 9.35m

↦ Breadth = 6m 45cm

45cm = 45/100m

= 0.45m

So, Breadth = 6.45m

____________

We know that,

$\large\blue{\underline{{\boxed{\textbf{Perimeter\:of\: rectangle\:=\:2×(l+b)}}}}}$

In which l is length of rectangle and b is breadth of rectangle.

Now, put the values

⇒2×(9.35 + 6.45)

⇒18.7 + 12.9

⇒31.6 m

Therefore,Perimeter of rectangle is 31.6 m