Question

find the perimeter of a a rectangle whose length is (-4a+9b) and breadth (5a-6b)​

Answer 1

$\mathfrak \red{perimeter = 2(l+b) </p><p> = 2(-4+9b+5a-6b) </p><p>= 10b+4a}$

Answer 2

answer for the question is is 18 A + 8b