Question

find the perimeter of a field consisting of a rectangle, an equilateral triangle and a semicircle show below

Answer 1

the perimeter is 90m

refer the attached for the method of the question

Answer 2

If the triangle is equilateral so the breadth of rectangle is 14 and the diameter of semi circle is also 14.
Let we find the perimeter of triangle = sum of all the sides.
so 14+14 + 14 = 42
perimeter of rectangle = 2 ( l+ b )
= 2 (14 +20 )
= 2 ( 34 )
2× 34
= 68
circumference of circle = 2 pie r
2 × 22/ 7 × 7
= 44
Total perimeter of field = 68 + 42 + 44
=154
154 - 28
= 126
hope it help
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