find the perimeter of a isoscacele triangle whose area is
WOWAMRAN5:
68.28 cm
Solution -
Area of a triangle = 1/2 * b * h
As it is an isosceles right triangle, b = h
Therefore, Area = 1/2 * b * b = 1/2 * b^2
200 = 1/2 * b^2
b^2 = 400
b = 20 cm
Therefore, b = h = 20 cm
Perimeter of a triangle = b + h + sqrt (b^2 + h^2)
= 20 + 20 + sqrt ((20)^2 + (20)^2)
= 40 + sqrt(400 + 400)
= 40 + sqrt(800)
= 40 + 20 sqrt 2 cm
= 40 + 20 * 1.414 (as sqrt 2 = 1.414)
= 68.28 cm
Answer - Perimeter of an isosceles right triangle = 68.28 cm
Area of a triangle = 1/2 * b * h
As it is an isosceles right triangle, b = h
Therefore, Area = 1/2 * b * b = 1/2 * b^2
200 = 1/2 * b^2
b^2 = 400
b = 20 cm
Therefore, b = h = 20 cm
Perimeter of a triangle = b + h + sqrt (b^2 + h^2)
= 20 + 20 + sqrt ((20)^2 + (20)^2)
= 40 + sqrt(400 + 400)
= 40 + sqrt(800)
= 40 + 20 sqrt 2 cm
= 40 + 20 * 1.414 (as sqrt 2 = 1.414)
= 68.28 cm
Answer - Perimeter of an isosceles right triangle = 68.28 cm
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