Question

find the perimeter of a quadrilateral whose four sides are 3 1/2 cm,5 5/12 cm,3 3/4 and 4 1/6 cm​

Answer 1

Perimeter = Sum of all sides

Perimeter = 3 1/2 + 5 5/12 + 3 3/4 + 4 1/6

$3\frac{1}{2} + 5\frac{5}{12} + 3\frac{3}{4} +4\frac{1}{6} =\frac{7}{2} +\frac{65}{12} +\frac{15}{4} +\frac{25}{6} \\=\frac{(7*6)+(65*1)+(15*3)+(25*2)}{12}\\ =\frac{42+65+45+50}{12} \\=\frac{202}{12} \\=\frac{101}{6}$

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Answer 2

Answer:

perimeter of a quadrilateral =sum of four sides

Step-by-step explanation:

$3 \frac{1}{2} = \frac{7}{2} \\ 5 \frac{5}{12} = \frac{65}{12} \\ 3 \frac{3}{4} = \frac{15}{4} \\ 4 \frac{1}{6} = \frac{25}{6}$

$\frac{7}{2} + \frac{65}{12} + \frac{15}{4} + \frac{25}{6} = \frac{42 + 65 + 45 + 50}{12} \\ = \frac{202}{12 } = \frac{101}{6}$