Question

find the perimeter of a rectangle field whose length is 6 time it width and which has an area equal to 40344 cm ²​

Answer 1

Answer:

1148 cm

Step-by-step explanation:

Given: Area = 40344 cm² and length is 6 times the breadth.

Area of l × b = 6b × b
Now,

6b × b = 40344
6b²      = 40344
b²         = $\frac{40344}{6} = 6724$

b           = 82

Now,
length = 82 × 6 = 492
breadth = 82

Perimeter = 2(l + b)

                 = 2(492 + 82)

                 = 2(574)

                 = 1148 cm

Therefore, the perimeter of the rectangle field is 1148 cm.