Question

find the perimeter of a rectangle where the length is 40 cm and the diagonal is 41 CM​

Answer 1

Answer:

98 cm

Step-by-step explanation:

Perimeter of a rectangle= 2(length+breadth)

Diagonal=

$\sqrt{ {l}^{2} + {b}^{2} }$

Put values;

$41 = \sqrt{ { 40}^{2} + {b}^{2} }$

${41}^{2} - {40}^{2} = {b}^{2}$

$81 = {b}^{2}$

$\sqrt{ {9}^{2} } = {b}^{2}$

$b = 9$

So, perimeter= 2(40+9)

=98cm

HOPE IT IS USEFUL

Answer 2

Answer:

Refer to the attachment above. ⬆️

hope it helps!!