Question

find the perimeter of a rectangle whoes lenth is 40cm and a diagonalis 41

Answer 1

Step-by-step explanation:

Given that length of the side of the rectangle is l=40cm and

the length of the diagonal is d=41cm

let breadth be bcm

Therefore, l² + b² = d²

⟹40² + b² =41²

⟹b² = 81

⟹b=9cm

we know that the perimeter of the rectangle is 2(l+b)=2(40+9)=98cm

hope it helps you

Answer 2

Step-by-step explanation:

$given \: that \: the \: length \: of \: the \: side \: of \: the \: rectangle \: is \: 1 = 40cm \: and$

$the \: length \: of \: the \: diagonal \: is \: d = 41cm$

$let \: the \: breadth \: be \: bcm$

$therefore {1}^{2} + {b}^{2} = {d}^{2}$

$= = > {40}^{2} + {b}^{2} = {41}^{2}$

$= = > {b}^{2} = 81$

$= = > b = 9cm$

we know that the perimeter of the rectangle is

$2(l + b) \\ 2(40 + 9) \\ = 98c$

hope it helps you ❤️

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