Find the perimeter of a rectangle whose:
2. 7
Area = 8----sq mm, length =5-----mm
3. 9
Show whole method/solution how to find it.
Answers
Answered by
0
p= l+b
p=5+x
5-8=b
b=3
p=l+b
p=5+3
=8
p=5+x
5-8=b
b=3
p=l+b
p=5+3
=8
phenomenolJay:
thanks
Answered by
0
Area=l×b 8=5×b b =8/5mm Therefore perimeter=2(5+8/5) =2{(25+8)/5} =2×33/5 Solve you get the answer
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