find the perimeter of a rectangle whose adjacent side are 3x-5y-4z and x-3y+5z
Answers
Answered by
14
The perimeter of rectangle is 2(l+b)
Then = 2(3x- 5y- 4z + x- 3y+5z)
6x-10y - 8z +2x-6y+10z
8x-16y +2z
Then = 2(3x- 5y- 4z + x- 3y+5z)
6x-10y - 8z +2x-6y+10z
8x-16y +2z
Answered by
5
Answer:
Answer is 8x-16y+2z
Step-by-step explanation:
First Perimeter of Rectangle=2(Length+Breadth)
So, as per formula:
2(3x-5y-4z+x-3y+5z)
Now will will add like terms.
2([3x+x]+[-5y-3y]+[-4z+5z]
2(4x-8y+z)
•Multiply 2 by whole bracket
So after multiplying we get
8x-16y+2a
Therefore perimeter of rectangle is 8x-16y+2z
•while adding like terms you have to multiply signs with the bracket pls remind this
If you dont understand it till now then pls refer the image ...
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