Math, asked by abhishek1881, 1 year ago

find the perimeter of a rectangle whose adjacent side are 3x-5y-4z and x-3y+5z

Answers

Answered by vivekrajChauhan
14
The perimeter of rectangle is 2(l+b)
Then = 2(3x- 5y- 4z + x- 3y+5z)
6x-10y - 8z +2x-6y+10z
8x-16y +2z
Answered by nnm1
5

Answer:

Answer is 8x-16y+2z

Step-by-step explanation:

First Perimeter of Rectangle=2(Length+Breadth)

So, as per formula:

2(3x-5y-4z+x-3y+5z)

Now will will add like terms.

2([3x+x]+[-5y-3y]+[-4z+5z]

2(4x-8y+z)

•Multiply 2 by whole bracket

So after multiplying we get

8x-16y+2a

Therefore perimeter of rectangle is 8x-16y+2z

•while adding like terms you have to multiply signs with the bracket pls remind this

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