Math, asked by abhishek1881, 11 months ago

find the perimeter of a rectangle whose adjacent side are 3x-5y-4z and x-3y+5z

Answers

Answered by vivekrajChauhan
14
The perimeter of rectangle is 2(l+b)
Then = 2(3x- 5y- 4z + x- 3y+5z)
6x-10y - 8z +2x-6y+10z
8x-16y +2z
Answered by nnm1
5

Answer:

Answer is 8x-16y+2z

Step-by-step explanation:

First Perimeter of Rectangle=2(Length+Breadth)

So, as per formula:

2(3x-5y-4z+x-3y+5z)

Now will will add like terms.

2([3x+x]+[-5y-3y]+[-4z+5z]

2(4x-8y+z)

•Multiply 2 by whole bracket

So after multiplying we get

8x-16y+2a

Therefore perimeter of rectangle is 8x-16y+2z

•while adding like terms you have to multiply signs with the bracket pls remind this

If you dont understand it till now then pls refer the image ...

pls mark me as BRAINLIEST

Thank you for watching my answer.Hope so you understand it better

Attachments:
Similar questions