Find the perimeter of a rectangle whose area= 2600m
2 and breadth
=50 m
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1
Answer:
204 m
Step-by-step explanation:
Area = l×b
2600 = l×50 m
2600÷50 = l
52=l
Therefore, length = 52 m
Perimeter = 2(l+b)
=2(52+50) m
=2×102 m
=204 m
The perimeter of the rectangle is 204.
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