Question

find the perimeter of a rectangle whose area=8 2/3 sq Mm and length = 5 7/9​

Answer 1

Step-by-step explanation:

find the perimeter of a rectangle whose area=8 2/3 sq Mm and length = 5 7/9mm

•l=5 7/9mm=52/9mm

•Area of rectangle=

8 2/3mm²=26/3mm²

area of rectangle=lb sq.units

=>52/9×b=26/3

=>b=26/3÷52/9

=>b=26/3×9/52

=>b=3/2mm

l=52/9mm,b=3/2mm

perimeter of rectangle=2(l+b)

=2(52/9+3/2)

=2(131/18)

=131/9mm

=14 5/9mm