Question

find the perimeter of a rectangle whose area is 120 sq. m and breadth is 10 m​

Answer 1

Answer:

So , first we have to find length

area = l×b

120=l×10

l = 120/10

l = 12 m

now ,perimeter = 2(l+b)

= 2(12+10)

=2(22)

=44 sq m