find the perimeter of a rectangle whose area is 44.1 sq m and breadth is 2.1 cm
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let the length be x.
area= l×b
44.1=x×2.1
we will take 2.1 at left side.so,it will be divided,
44.1÷2.1=22
so length is 22 cm.
perimeter=2(l+b)
2(22+2.1)
2×24.1=48.2 cm
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