Question

Find the perimeter of a rectangle whose area is 500 cm2 and breadth is 20 cm.

answer it pls

Answer 1

As per the question we know the area of rectangle and its breadth. we have to find its perimeter. So let's find!!

$\:$

$\sf\red{As \: we \: know,}$

Area of Rectangle = Length × Breadth

Let the Length be x.

Then,

500 cm² = x × 20 cm

x =$\sf\red{ 500 ÷ 20}$

x = $\sf\red{25 \: cm}$

$\:$

Then,

Perimeter = 2( l + b)

Perimeter = 2(25 + 20)

Perimeter = 50 + 40

$\:$

$\boxed{\mathfrak{Hence,The \: perimeter \: of \: the \: rectangle \: is \: 90 cm.}}$

Verification:

As we know,

Area = l × b

Area = $\sf\red{25 × 20}$

Area = 500 cm²

$\sf\green{500 cm² = 500 cm²}$

Henceforth Verified!!

Answer 2

✬Question✬

• Find the perimeter of a rectangle whose area is 500$\rm{cm}^{2}$ and breadth is 20 cm.

✬To Find✬

• Perimeter of a rectangle = ?

✬Given✬

• Area of rectangle = 500$\rm{cm}^{2}$cm
• Breadth of rectangle = 20 cm

✬Formula used✬

• Perimeter of rectangle = 2(l + b)
• Area of rectangle = length × breadth

✬Solution✬

Let us consider that,

• Length = l

Area of rectangle = l × b

$\implies$ $\sf{500 = l \times 20}$

$\implies$ $\sf{l = \cancel\frac{500}{20}}$

$\implies$ $\sf{l = 25 cm}$

Therefore,The length of rectangle is 25 cm.

Perimeter of rectangle = 2(l + b)

$\implies\sf{Perimeter = 2(25 +20)}$

$\implies\sf{Perimeter = 2(45)}$

$\implies\sf{Perimeter = 90 cm}$

$\red{\sf{Therefore,The \: perimeter \: of \: rectangle \: is \: 90 \: cm}}$