find the perimeter of a rectangle whose area is 600 cm square and breadth is 25 cm.
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dimensions of the rectangle
breadth =b=25 cm
let length = l cm
area =600cm²
lb=600
l*25 =600
l= 600/25
l=24 cm
therefore
perimeter of the rectangle = 2(l+b)
= 2(24+25)
=2*49
=98 cm
breadth =b=25 cm
let length = l cm
area =600cm²
lb=600
l*25 =600
l= 600/25
l=24 cm
therefore
perimeter of the rectangle = 2(l+b)
= 2(24+25)
=2*49
=98 cm
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