Math, asked by poonamadesara, 1 month ago

Find the perimeter of a rectangle whose area is 650 sq.cm and its breadth is 13cm.

The side of a square is 70cm. Find its area and perimeter,

Answers

Answered by suhanii27
3

Step-by-step explanation:

area of rectangle = 650 sq.cm

L × b = 650 sq.cm

L × 13 = 650 sq.cm

L = 650 / 13

L = 50 cm

perimeter of rectangle = 2 ( L + B )

= 2 ( 50 + 13 )

= 2 ( 63 )

= 126 cm

Answered by debarghyamurmu5
0

Answer:

Perimeter of a rectangle whose are is 650 sq.cm and it's breadth is 13cm.

(Answer) - 125cm

Q.2. The side of a square is 70cm. Find its area and perimeter.

(Answer) - Area = 4,900 sq.cm

Perimeter = 280 cm

Step by step explanation:

Q.1. Area=650 sq.cm

breadth=13 cm

:. length of the rectangle= area/breadth

= (650/13) cm

= 50 cm

Now, Perimeter of the rectangle = 2(length+breadth) unit

=2( 50+ 13) cm

=2(63) cm

=(2×63) cm

= 126 cm

Q.2.i. Side = 70cm

Area of a square = (side×side) sq.unit

= (70×70) sq.cm

= 4,900 sq.cm

ii. Side= 70cm

Perimeter of a square = (4×side) unit

= (4×70) cm

= 280cm

Hopefully it will help you. Mark as brainliest.

Similar questions