Find the perimeter of a
rectangle whose area is 650cm2 and breadth is 13cm
Answers
Answered by
3
AR. =l x b
650=13 x l
L=650/13
L=50
P=2(l+b)
=2(13+50)
=2(43)
=86cm
650=13 x l
L=650/13
L=50
P=2(l+b)
=2(13+50)
=2(43)
=86cm
Swarup1998:
50+13=63
Answered by
23
Given data is
Area of the rectangle ( A ) = 650 cm²
Breadth ( b ) = 13 cm
Solution :
Let us take the length of the rectangle be a cm
We know that, the area of the rectangle is
( Breadth * Length ) unit²
= 13 * a cm²
⇒ 13a = 650 ( given )
⇒ a = 50
So, length of the rectangle is 50 cm
Therefore, the perimeter of the rectangle is
= 2 ( length + breadth ) units
= 2 ( a + b ) cm
= 2 ( 50 + 13 ) cm
= 2 * 63 cm
= 126 cm
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