Math, asked by Anonymous, 4 months ago

Find the perimeter of a rectangle whose area is 650sq.cm and its breadth is 13cm​

Answers

Answered by Anonymous
3

area = 650 cm^2

breadth = 13cm

length = ?

perimeter = ?

area = l * b

area = 13 * b

650 = 13b

b = 650/13

breadth = 50cm

perimeter = 2(l+b)

perimeter = 2(50+13)

perimeter = 2(63)

perimeter = 126cm

Answered by ItzMissLegend
79

Area of the rectangle =650 cm

Area of the rectangle =650 cm 2

Area of the rectangle =650 cm 2

Area of the rectangle =650 cm 2 Breadth =13 cm

Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth

Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13

Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cm

Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cmPerimeter =2(length +breadth)

Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cmPerimeter =2(length +breadth)=2(50+13) cm

Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cmPerimeter =2(length +breadth)=2(50+13) cm=2(63)

Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cmPerimeter =2(length +breadth)=2(50+13) cm=2(63)=126 cm

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