Find the perimeter of a rectangle whose area is 650sq.cm and its breadth is 13cm
Answers
area = 650 cm^2
breadth = 13cm
length = ?
perimeter = ?
area = l * b
area = 13 * b
650 = 13b
b = 650/13
breadth = 50cm
perimeter = 2(l+b)
perimeter = 2(50+13)
perimeter = 2(63)
perimeter = 126cm
Area of the rectangle =650 cm
Area of the rectangle =650 cm 2
Area of the rectangle =650 cm 2
Area of the rectangle =650 cm 2 Breadth =13 cm
Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth
Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13
Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cm
Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cmPerimeter =2(length +breadth)
Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cmPerimeter =2(length +breadth)=2(50+13) cm
Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cmPerimeter =2(length +breadth)=2(50+13) cm=2(63)
Area of the rectangle =650 cm 2 Breadth =13 cmLength = Area / breadth=650/13=50 cmPerimeter =2(length +breadth)=2(50+13) cm=2(63)=126 cm