Math, asked by naitik3lislaxmieduin, 2 months ago

Find the perimeter of a rectangle whose area is 750 cm2

and whose breadth is 15 cm.
Step by step explanation​

Answers

Answered by stuprajin6202
3

130 cm

Step-by-step explanation:

P=2l+2A

l=2·15+2·750

15=130cm

Answered by Anonymous
26

Let the Length of the rectangle be x and we've breadth as 15 cm.

  • Area of Rectangle = 750 cm²

We know that:

 \bullet \ {\purple{\underline{\boxed{\sf{ Area _{(Rectangle)} = length \times breadth }}}}} \\ \\ \colon\implies{\sf{ 750 = x \times 15 }} \\ \\ \colon\implies{\sf{ \cancel{ \dfrac{750}{15} } = x }} \\ \\ \colon\implies{\sf{ x = 50 \ cm }} \\

 \\ {\sf{ So, the \ length \ of \ the \ Rectangle \ is \ 50 \ cm. }}

Now, we've to find the Perimeter of the Rectangle and we know that:-

  • Length = 50 cm
  • Breadth = 15 cm

 \bullet \ {\pink{\underline{\boxed{\sf{ Perimeter _{(Rectangle)} = 2(l+b) }}}}} \\ \\ \colon\implies{\sf{ Perimeter _{(Rectangle)} = 2(50+15) }} \\ \\ \colon\implies{\sf{ Perimeter _{(Rectangle)} = 2(65) }} \\ \\ \colon\implies{\sf{ Perimeter _{(Rectangle)} = 2 \times 65 }} \\ \\ \colon\implies{\sf{ Perimeter _{(Rectangle)} = 130 \ cm }}

Hence,

 \\ {\underline{\sf\red{The \ Perimeter \ of \ the \ Rectangle \ is \ 130 \ cm. }}}

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