Question

find the perimeter of a rectangle whose area is 96 sq.m and its breadth is 8cm​

Answer 1

Step-by-step explanation:

So this is the answer you require. her perimeter is 40 cm and the length of 8 cm

Answer 2

Answer:

$\red { Perimeter \: of \: the \: rectangle (P)}\green {= 40\:cm }$

Step-by-step explanation:

$Given \: Breadth \: of \: a \: rectangle (b) = 8\:cm$

$Let \: the \: length = l \:cm$

$Area \: of \: the \: rectangle (A) = 96 \:m^{2}$

$\implies \pink { l \times b } = 96$

$\implies l \times 8 = 96$

$\implies l = \frac{96}{8} = 12 \:cm$

$\orange {Perimeter \: of \: the \: rectangle (P) = 2(l+b)}$

$= 2( 12 + 8 ) \\= 2 \times 20 \\= 40 \:cm$

Therefore.,

$\red { Perimeter \: of \: the \: rectangle (P)}\green {= 40\:cm }$

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