Question

Find the perimeter of a rectangle whose area is 96 sq m and its breadth is 8 m
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Answer 1

Answer:

Area of the rectangle=96 sq m.

Breadth of the rectangle=8m

We know that

Area of a rectangle=Length x Breadth

Therefore,

Length=Area/Breadth

Or, Length=96/8m

Or, Length=12m

Therefore,

perimeter of the rectangle

=2*(Length+Breadth)

=2*(12+8) m

=2*20m

=40m

Answer: The perimeter of the rectangle is 40m

Step-by-step explanation:

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Answer 2

Given :

• Area of Rectangle = 96 m².

• Breadth of rectangle = 8 m.

To find :

• Perimeter of the rectangle =?

Formula Used :

• Area of Rectangle = length x breadth

• Perimeter of the rectangle = 2( length + breadth)

Step-by-step explanation :

1st Case :

It is Given that :

Area of Rectangle = 96 m².

Breadth of rectangle = 8 m.

We know that,

Area of Rectangle = length x breadth

Substituting the values in the above formula, we get,

96 = length x 8

Or, lenght = 96/8

length = 12

Therefore, Length of the rectangle = 12 m.

2nd Case :

Now, We know that,

Length of Rectangle = 12 m.

Breadth of rectangle = 8 m.

So,

Perimeter of the rectangle = 2( length + breadth)

Substituting the values in the above formula, we get,

= 2(12 + 8)

= 2(20)

= 40.

Therefore, Perimeter of the rectangle = 40 m.