Question

Find the perimeter of a rectangle whose breadth is 9 CM and diagonal is 41 CM​

Answer 1

Answer:

diagonal = hypotenuse = 41 cm

breadth = perpndicular = 9 cm

h² = b² + p²

(41) ² = b² + (9)²

1681 = b² + 81

1681 - 81 = b²

1600 = b²

b= 40 cm

length = base = 40 cm

perimeter = 2(l+b)

= 2(40 + 9)

= 2×49

= 98 cm

Answer 2

Answer:⤵️⤵️

${d}^{2} = {l}^{2} + {b}^{2} \\ {41}^{2} = {l}^{2} + {9}^{2} \\ {41}^{2} - {9}^{2} = {l}^{2} \\ 1681 - 81 = {l}^{2} \\ 1600 = {l}^{2} \\ \sqrt{1600} = l \\ 40 = l$

perimeter =2(l+b)

p=2(40+9)

p=2*49

p=98cm

I hope it will helps you❤

plz mark me as a brainlist❤