Find the perimeter of a rectangle, whose dimensions are 5a+8b-4 and 2a-3b+7.
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Answer:
14a+10b+6
Step-by-step explanation:
perimeter of rectangle =2(l+b)
=2[(5a+8b-4)+(2a-3b+7)]
=2[7a+5b+3]
=14a+10b+6
Answered by
0
Step-by-step explanation:
Dimensions are=5a+8b-4 and 2a-3b+7
Now,
perimeter =2(l+b)
2{(5a+8b-4)+(2a-3b+7)}
2{5a+8b-4+2a-3b+8}
2{7a+5b+3}
14a+10b+6
so, perimeter of rectangle is 14a+10b+6
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