Find the perimeter of a rectangle whose lenght is 8cm and the daigonal is 10cm
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All anges of a rectangle are 90°
Let the quadrilateral be ABCD
In ∆ ABC
AB is 8 cm...... side of rectangle
AC is 10cm .... diagonal
By Pythagoras theorem
AC² = AB²+ BC²
100 = 64 + BC²
100-64 = BC²
BC = ✓36
BC = 6 cm
Length of rectangle is 8 cm and breadth of rectangle is 6 cm
Perimeter of a rectangle= 2(l+b)
= 2(8+6)
= 2(14)
= 28 cm²
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