Math, asked by gatharox9444, 1 year ago

Find the perimeter of a rectangle whose lenght is 8cm and the daigonal is 10cm

Answers

Answered by anjali17103
2

All anges of a rectangle are 90°

Let the quadrilateral be ABCD

In ∆ ABC

AB is 8 cm...... side of rectangle

AC is 10cm .... diagonal


By Pythagoras theorem

AC² = AB²+ BC²

100 = 64 + BC²

100-64 = BC²

BC = ✓36

BC = 6 cm


Length of rectangle is 8 cm and breadth of rectangle is 6 cm


Perimeter of a rectangle= 2(l+b)

= 2(8+6)

= 2(14)

= 28 cm²



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