find the perimeter of a rectangle whose length=22.5m and the breadth= 16 dm
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Let length of Rectangle be L and Breadth be B
Now, According to Given question,
L = 22.5 m and B = 16 dm
We Know, 1 dm = 0.1 m
Thus 16 dm = 16 * 0.1 m
= 1.6 m
So,
Breadth, B = 1.6 m
Thus as we know, Perimeter of Rectangle = 2 (L + B)
So, Perimeter = 2 (22.5 + 1.6)
= 2 * 24.1
= 48.2 m
Thus the perimeter of the rectangle is 48.2 m.
Now, According to Given question,
L = 22.5 m and B = 16 dm
We Know, 1 dm = 0.1 m
Thus 16 dm = 16 * 0.1 m
= 1.6 m
So,
Breadth, B = 1.6 m
Thus as we know, Perimeter of Rectangle = 2 (L + B)
So, Perimeter = 2 (22.5 + 1.6)
= 2 * 24.1
= 48.2 m
Thus the perimeter of the rectangle is 48.2 m.
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