Find the perimeter of a rectangle whose length and breadth are (x2 + y2) meters and 2xy meters respectively.
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Answer:
perimeter = 2(l+b)
2(x²+y²+2xy)
2(x+y)² [x²+y²+2xy=(x+y)²]
2x²+2y²
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Perimeter of a Rectangle is 2(L+B)
L = x² + y² = (x+y)²
B = 2xy
Perimeter = 2[(x+y)²+ 2xy]
2x² + 2y² + 4xy
OR
2(x×x) + 2(y×y) + 4(x×y)
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