Question

find the perimeter of a rectangle whose length equal to 22.5 metre and breadth equal to 16 DM.
ans- is 48.2 m
but I don't know how to solve it
please help me​

Answer 1

Answer:

perimeter of rectangle = 2(l+b)

= 2(22.5+16)

= 2(38.5)

= 77 m^2

Answer 2

Answer:

Let,

Length be L

Breadth be B

Now, A/Q

L = 22.5 m

B = 16 dm

We Know,

1 dm = 0.1m

Thus 16 dm = 16 × 0.1 = 1.6m

So,

Breadth, B = 1.6m

As We Know

Rectangle = 2(L+B)

So, = (22.5 + 1.6)

Perimeter of Rectangle

. = 2 (L + B)

. = 2 × 24.1

. = 48.2m

Thus the perimeter of the rectangle is 48.2m

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