Find the perimeter of a rectangle whose length is 12cm and
diagonal is 13cm
Answers
Answer:
First find the breadth
Use Pythagoras theorem
AB is the breadth ( h)
AB square = 13 square -12 square
169cm square- 144 square
AB=√25
AB=5cm
Breadth=5cm
Perimeter of rectangle = 2×(l+b)
=2×17 cm
=34cm
Given,
The rectangle length l = 12cm
The rectangle's diagonal d = 13cm
To Find,
The perimeter of the rectangle.
Solution,
Given that,
Length of the rectangle l = 12cm
Diagonal of the rectangle d = 13cm
We need to find the perimeter.
By using the Pythagoras equation,
d² = l²+w²
13² = 12²+w²
w² = 13² - 12²
w²=169-144
w²=25
w=5
Therefore, the perimeter of the rectangle
P = 2(l+w)
P= 2(12+5)
p=2×17
P = 34cm
The perimeter of the rectangle whose length of 12cm and diagonal of 13cm is 34cm.