Find the perimeter of a rectangle whose length is 24 cm. and diagonal
is 26 cm
Answers
Answered by
2
By using Pythagoras theorum
H^2=B^2+P^2
26^2=24^2+P^2
676=648+p^2
676-648=P^2
28 under root
Now find the perimeter yourself
Mark as brainliest pls
H^2=B^2+P^2
26^2=24^2+P^2
676=648+p^2
676-648=P^2
28 under root
Now find the perimeter yourself
Mark as brainliest pls
Answered by
11
Length(l) = 24cm
Diagonal(d) = 26cm
Perimeter(p) = 2(l + b)
= 2(l + 2) √d² - l²
= 2(24 + 2) √26² - 24²
= 68cm
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