Question

Find the perimeter of a rectangle whose length is

2ab + 7b2 + 7a2 and breadth is 5ab + 3a2​

Answer 1

Answer:

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Step-by-step explanation:

petimetery= 2(l+b).

=>2( 2ab + 7b² + 7a² + 5ab + 3a²)

=> 2(7ab+ 11a² + 7b²)

=> 14ab + 11a² + 7b²

Answer 2

Answer:

20a² + 14b² + 14ab

Step-by-step explanation:

Given,

Length ( l ) = 2ab + 7b² + 7a²

Breadth ( b ) = 5ab + 3a²

To find : Perimeter ( rectangle ) = ?

Formula : -

Perimeter ( rectangle ) = 2 ( l + b )

Perimeter ( rectangle )

= 2 ( 2ab + 7b² + 7a² + 5ab + 3a² )

= 2 ( 7a² + 3a² + 7b² + 2ab + 5ab )

= 2 ( 10a² + 7b² + 7ab )

= 20a² + 14b² + 14ab