Question

find the perimeter of a rectangle whose length is 40 cm and diagonal is 41 CM ​

Answer 1

Answer:

daigonal= 41cm

length = 40cm

By Pythagoras, H^2=P^2+B^2

(41)^2=P^2+ (40)^2

1681- 1600= P^2

√81=P

P= 9cm (width)

Now

perimeter of rectangle= 2(l+b)= 2(40+9)= 98cm