find the perimeter of a rectangle whose length is 40 cm and a diagonal is 41 cm
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Length(l) = 40cm
Breadth(b) = ?
Diagonal (d) = 41cm
d^2 = l^2 + b^2
(41)^2 = (40)^2 + b^2
1681 = 1600 + b^2
b^2 = 1681 - 1600 = 81
b = √81 = 9
Breadth(b) = 9cm
Perimeter = 2(l+b) = 2 X (40+9) = 2 X 49 = 98cm
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Breadth(b) = ?
Diagonal (d) = 41cm
d^2 = l^2 + b^2
(41)^2 = (40)^2 + b^2
1681 = 1600 + b^2
b^2 = 1681 - 1600 = 81
b = √81 = 9
Breadth(b) = 9cm
Perimeter = 2(l+b) = 2 X (40+9) = 2 X 49 = 98cm
Plz mark it as brainliest....
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