Find the perimeter of a rectangle whose length is 40 cm. and a diagonal is 41 cm. Don't Post Inappropriate Answers!
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Answer:
P=98cm
Step-by-step explanation:
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Step-by-step explanation:
In A ACD
AB = CD = 40 CM
AD=41 CM
ZACD = 90° ( RECTANGLE HAS 90° =
ON ALL THE BOTH SIDES)
By Pythagoras theorem
AD? = AC? + CD?
AD? - CD? = AC²
(41)2 - (40)2 = AC
1681 - 1600 = 81 = AC?
V81 = AC
AC = 9 CM
Perimeter of Rectangle ABCD = 2 (l+b)
= 2(40 + 9) = 2(49) = 98 CM
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