Question

Find the perimeter of a rectangle whose length is 40 cm and a diagnol is 41 cm

Answer 1

"""""here is solution""""""

Answer 2

$\bf\huge\color{blue}\mathcal{HEY\:\:FRIEND\:\:}\mathbb{:)}\\\bf\large\color{violet}\mathcal{Here\:is\: your\: answer}$

EDIT : I took length of diagonal by mistake.

Real perimeter = 2(l+b)
= 2(40+9)
= 2(49)
= $\bf\textit{98\:cm}$

Hope this helps!!!!