Question

Find the perimeter of a rectangle whose length is 40cm and diagonal 41cm.​

Answer 1

In Δ ACD

AB = CD = 40 CM

AD=41 CM

∠ACD = 90° ( RECTANGLE HAS 90° ON ALL THE BOTH SIDES)

By Pythagoras theorem

AD² = AC² + CD²

AD² - CD² = AC²

(41)² - (40)² = AC²

1681 - 1600 = 81 = AC²

√81 = AC

AC = 9 CM

Perimeter of Rectangle ABCD = 2 (l+b)

= 2(40 + 9) = 2(49) = 98 CM.....

hope this will help you.

thank you......

Answer 2

Answer:

162 cm square

Step-by-step explanation:

Perimeter = 2(l+b)

p=2(40+41)

p=2×81

p=162

Ans=162

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