Find the perimeter of a rectangle whose length is (4a-3b-6c) units and breadth is (5a- 4b+2c) units.
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Answer:
2× (l+b)
2× (4a-3b-6c) +(5a-4b+2c)
2× (4a+5a-3b-4b-6c+2c)
2× ( 9a-7b-4c)
18a-14b-8c is your answer
Extra Information
formula use for taking out the Perimeter of a rectangle = 2×(l+ b) and formula use for taking out the Area of a rectangle = l× b
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