Question

find the perimeter of a rectangle whose length is 5 1/3cm& breadth is 2 1/2​

Answer 1

Step-by-step explanation:

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Answer 2

Given :

⬤ Length of Rectangle = 5(1/3) cm

⬤ Breadth of Rectangle = 2(1/2) cm

To Find :

⬤ Perimeter of Rectangle .

Formula Used :

$\sf[\:{Perimeter\:of\:Rectangle=2(l+b)}\:]$

Solution :

• Length = 5(1/3) = 16/3
• Breadth = 2(1/2) = 5/2

Now :

According to the Formula :

2 (l + b)

$\dashrightarrow\sf{2\:\bigg(\dfrac{16}{3}+\dfrac{5}{2}\bigg)}$

$\dashrightarrow\sf{2\:\bigg(\dfrac{2\times{16}+3\times{5}}{6}\bigg)}$

$\dashrightarrow\sf{2\:\bigg(\dfrac{32+15}{6}\bigg)}$

$\dashrightarrow\sf{2\:\bigg(\dfrac{47}{6}\bigg)}$

$\dashrightarrow\sf{\dfrac{47}{3}}$

$\dashrightarrow\sf{15\dfrac{2}{3}}$

Therefore , The Perimeter of the Rectangle is 47/3 or 15(2/3) .

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Related Formulas :

• Perimeter of Rectangle = 2 (l + b)
• Area of Rectangle = l × b
• Perimeter of Square = 4 × Side
• Area of Square = Side²

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