Question

find the perimeter of a rectangle whose length is 7.5 cm and diagonal is 8.5 CM​

Answer 1

hey amigo ,

your answer↩⬇

solution :

given length =7.5

diagonal =8.5

as we know that the rectangle makes 90 degree angle at the vertices

so, by using Pythagoras theorem

let diagonal be hypotenuse ,length be the perpendicular and breadth be te base

therefore,

${h}^{2} = {p}^{2} + {b}^{2} \\ or \: {b}^{2} = {h}^{2} - {p}^{2} \\ \\ b = \sqrt{ {h}^{2} - {p}^{2} } \\ \\ b = \sqrt{ {8.5}^{2} - {7.5}^{2} } \\ \\ b = \sqrt{72.25 - 56.25} \\ \\ b = \sqrt{16} = 4 \\ \\ now \: perimeter \: of \: rectangle \: \\ \\ = 2(l + b) \\ \\ = 2(7.5 + 4) = 23 \: cm$

hope it's helpful

Answer 2

Answer:

sorry I don't know ‍♀