Question

Find the perimeter of a rectangle whose length is 9 CM and diagonal is 41 CM​

Answer 1

Answer:

length of rectangle =9cm

breadth of rectangle =41cm

perimeter = ?

=2(l+b)

=2(9+41)

=2×50

=100cm

Therefore perimeter of rectangle is 100cmsquare

Answer 2

Step-by-step explanation:

diagonal = 41cm

length = 9cm

breadth = x.

now,

(diagonal) ² = (length)² +(breadth) ²

(41)² = (9)² + (x) ² = 1681-81 = (x) ²

1600= x² = 40 = x = breadth

now,

Perimeter of rectangle = 2(L+B)

2(9+40) = 2× 49 = 198 CM