Find the perimeter of a rectangle whose length is sin^2 theta and whose breadth is cos^2 theta
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Answer:
here, l=sin^2 theta and b=cos^2 theta
Perimeter of a rectangle= 2(l+b) = 2( sin^2 θ +cos^2 θ)
Using the trigonometric identity, sin^2 θ +cos^2 θ=1
Perimeter of a rectangle= 2 * 1 = 2
Therefore, Perimeter of a rectangle= 2 units
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Perimeter=2
OR
Perimeter=2unit
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