Question

Find the perimeter of a rectangle whose one side
measures 20 m and the diagonal is 29 m.
(a) 98 m
(b) 82 m
(c) 80 cm
(d) 100 cm​

Answer 1

Answer:

82m

Step-by-step explanation:

by pythagoras theorem one side is equal to

841-400=$\sqrt{x}$

x=21m

perimeter=2(l+b)

=2(20+21)

=82m

Answer 2

SOLUTION:-

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Given:

A rectangle whose one side measure 20m & the diagonal is 29m.

To find:

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The perimeter of rectangle.

Explanation:

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Rectangle: A rectangle is 2D shape in geometry,having 4 sides & 4 corners.

It's two sides meet at right angle (90)°.

Formula:

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•Perimeter of rectangle= 2(L + B)

•Area of rectangle = Length × breadth.

•Length of Diagonal= d= √L² + W²

According to the question:

• Length= 20m
• Breadth= 29m

Diagonal²= L² + W²

29²= √20² + W²

W²= 29² - 20²

W² = 841 - 400

W² = 441

W= √441

W= 21m

Perimeter= 2(l+b)

=) 2(20m+ 21m)

=) 2(41m)

=) (2× 41)m

=) Perimeter of rectangle= 82m

Option (b)✓

:)